876. Middle of the Linked List

# Definition for singly-linked list. # class ListNode: # def __init__(self, x): # self.val = x # self.next = None class Solution: def middleNode(self, head): """ :type head: ListNode :rtype: ListNode """ fast = slow = head while(fast != None and fast.next != None): fast = fast.next.next slow = slow.next return slow
Error: fast.next.next need to make sure fast.next != None

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