Assembly

.data cau1: .asciiz "\nNhap vao 1 chuoi: " endl: .asciiz "\n" cau1_2: .asciiz "\nChuoi vua nhap: " declaration: .asciiz "\nNhap 1 ky tu: " cau2a: .asciiz "Ky tu lien truoc: " cau2b: .asciiz "Ky tu lien sau: " cau3: .asciiz "Ky tu thuong: " cau4_1: .asciiz "\nNhap so thu nhat: " cau4_2: .asciiz "\nNhap so thu hai: " cau4_3: .asciiz "\nTong: " cau4_4: .asciiz "\nHieu: " cau4_5: .asciiz "\nTich: " cau4_6: .asciiz "\nThuong: " cau4_7: .asciiz " | Du: " stNhapA: .asciiz "Nhap gia tri so A: " stNhapB: .asciiz "Nhap gia tri so B: " stLon: .asciiz "So Lon Hon La: " chuSo: .asciiz " la chu so\n" chuCai: .asciiz " la chu cai\n" chuInHoa: .asciiz " la chu in hoa\n" NhapN: .asciiz "\nNhap vao 1 so: " KetQua: .asciiz "\nTong tu " den: .asciiz " den " LA: .asciiz " la: " mang: .word 0:100 NhapMang: .asciiz "\nNhap so phan tu mang: " MangVuaNhap: .asciiz "\nMang vua nhap: " KhoangTrang: .asciiz " " str: .space 100 # chu?i ban ??u revstr: .space 100 # chu?i sau khi ??o ng??c NhapChuoi: .asciiz "\nNhap vao 1 chuoi: " DaoNguoc: .asciiz "\nChuoi vua duoc dao nguoc: " .text main: # Nhap / xuat 1 chuoi la $a0, cau1 addi $v0, $0, 4 syscall addi $a1, $0, 40 # khoi tao bo dem a1 de nhap chuoi voi 40 ki tu addi $v0, $0, 8 syscall addi $s0, $a0, 0 # luu chuoi vua nhap vao $s0 la $a0, cau1_2 # in thong bao addi $v0, $0, 4 syscall addi $a0, $s0, 0 # xuat chuoi addi $v0, $0, 4 syscall # Nhap 1 ki tu, xuat ra ki tu truoc, sau no: la $a0, declaration # in thong bao nhap addi $v0, $0, 4 syscall addi $v0, $0, 12 # Nhap syscall addi $s0, $v0, 0 la $a0, endl # xuong hang addi $v0, $0, 4 syscall la $a0, cau2a # in thong bao xuat 1 addi $v0, $0, 4 syscall addi $a0, $s0, -1 # truoc addi $v0, $0, 11 # xuat syscall la $a0, endl addi $v0, $0, 4 syscall la $a0, cau2b # in thong bao xuat 2 addi $v0, $0, 4 syscall addi $a0, $s0, 1 # sau addi $v0, $0, 11 # xuat syscall la $a0, endl # xuong hang addi $v0, $0, 4 syscall # Nhap 1 ki tu in hoa, xuat ra ki tu thuong la $a0, declaration # in thong bao nhap addi $v0, $0, 4 syscall addi $v0, $0, 12 # nhap ki tu syscall addi $s0, $v0, 32 # Bien thanh ki tu thuong la $a0, endl # xuong hang addi $v0, $0, 4 syscall la $a0, cau3 # in thong bao xuat addi $v0, $0, 4 syscall addi $a0, $s0, 0 # xuat ket qua addi $v0, $0, 11 syscall # Nhap 2 so, tinh tong, hieu, tich, thuong # Nhap so thu nhat: la $a0, cau4_1 # thong bao nhap 1 addi $v0, $0, 4 syscall addi $v0, $0, 5 # nhap so thu nhat syscall add $s0, $0, $v0 # Luu so thu nhat vao $s0 # Nhap so thu 2: la $a0, cau4_2 # in thong bao nhap thu 2 addi $v0, $0, 4 syscall addi $v0, $0, 5 # nhap so thu hai syscall add $s1, $0, $v0 # Luu so thu hai vao $s1 # Tinh tong: la $a0, cau4_3 # in thong bao xuat tong addi $v0, $0, 4 syscall add $s2, $s0, $s1 # tinh tong addi $a0, $s2, 0 # xuat ket qua addi $v0, $0, 1 syscall # Tinh hieu la $a0, cau4_4 # in thong bao xuat hieu addi $v0, $0, 4 syscall sub $s2, $s0, $s1# tinh hieu addi $a0, $s2, 0 # Xuat ket qua addi $v0, $0, 1 syscall # Tinh tich: la $a0, cau4_5 # in thong bao xuat tich addi $v0, $0, 4 syscall mult $s0, $s1 # nhan 2 so mflo $s2 # bo ket qua vua tinh duoc vao $s2 addi $a0, $s2, 0 # Xuat ket qua addi $v0, $0, 1 syscall # T?nh th??ng la $a0, cau4_6 # in thong bao xuat thuong addi $v0, $0, 4 syscall div $s0, $s1 # chia 2 so mflo $s2 # xuat phan chia het vao $s2 mfhi $s3 # xuat phan du vao $s3 addi $a0, $s2, 0 # xuat thuong addi $v0, $0, 1 syscall la $a0, cau4_7 # in thong bao du addi $v0, $0, 4 syscall addi $a0, $s3, 0 # Xuat phan du addi $v0, $0, 1 syscall la $a0, endl # xuong hang addi $v0, $0, 4 syscall # Nhap 2 so, tim so lon hon: NhapSoThuI: la $a0, stNhapA # in thong bao nhap 1 addi $v0, $0, 4 syscall addi $v0, $0, 5 # nhap so thu nhat: syscall addi $s1, $v0, 0 # luu vao $s1 NhapSoThuII: la $a0, stNhapB # in thong bao nhap 2 addi $v0, $0, 4 syscall addi $v0, $0, 5 # nhap so thu hai: syscall addi $s2, $v0, 0 # luu vao $s2 # thu?t to?n kh?ng c?n d?ng l?nh ?i?u ki?n: # int c = a - b; # int k = (c >> 31) & 0x1; # int max = a - k * c; # ?? tham kh?o t?i: http://stackoverflow.com/questions/4772780/explain-this-snippet-which-finds-the-maximum-of-two-integers-without-using-if-el sub $s3, $s1, $s2 # s3 = s1 - s2 sra $s4, $s3, 31 # s4 = s3 >> 31 and $s4, $s4, 1 # s4 = s4 & 1 mult $s4, $s3 mflo $s5 # s5 = s4 * s3 sub $s6, $s1, $s5 # s6 = s1 - s5 => Gi? tr? c?n t?m la $a0, stLon # in thong bao xuat ket qua addi $v0, $0, 4 syscall addi $a0, $s6, 0 # xuat ket qua addi $v0, $0, 1 syscall # Nhap 1 ki tu, xet la chu thuong, chu hoa hay so la $a0, declaration # in thong bao nhap addi $v0, $0, 4 syscall addi $v0, $0, 12 # nhap syscall addi $s0, $v0, 0 # luu vao $s0 la $a0, endl # xuong hang addi $v0, $0, 4 syscall addi $a0, $s0, 0 #in ki tu vua nhap addi $v0, $0, 11 syscall #xet ma ASCII # chu so subi $s2, $s0, 58 # so sanh ma ASCII bltz $s2, laChuSo # neu thoa thi in ra chu so # chu in hoa subi $s4, $s0, 91 # so sanh ma ASCII bltz $s4, laChuInHoa # neu thoa thi in ra chu in hoa # chu cai subi $s3, $s0, 123 # so sanh ma ASCII bltz $s3, laChuThuong # neu thoa thi in ra chu thuong j fin # sai thi nhay den fin laChuSo: la $a0, chuSo # in ket qua addi $v0, $0, 4 syscall j fin3 # sai thi nhay den fin 3 laChuInHoa: la $a0, chuInHoa # in ket qua addi $v0, $0, 4 syscall j fin2 # sai thi nhay den fin 2 laChuThuong: la $a0, chuCai # in ket qua addi $v0, $0, 4 syscall fin2: fin: fin3: # Nhap so phan tu roi nhap tung phan tu cua mang, in ra mang ra man hinh: #Nhap so luong phan tu la $a0, NhapMang # in thong bao nhap so luong addi $v0, $0, 4 syscall addi $v0, $0, 5 # nhap so luong syscall addi $s0, $v0, 0 # luu so luong phan tu vao $s0 addi $s1, $s0, 0 # s1 = s0 la $t0, mang # gan dia chi mang vao $t0 do: # Nhap tung phan tu beq $s1, 0, ndo # s1 = 0 thi nhay sang ndo addi $v0, $0, 5 # nhap phan tu syscall sw $v0, ($t0) # luu vao $t0 addi $s1, $s1, -1 # giam di so luong can nhap di 1 addi $t0, $t0, 4 # t0 = t0 + 4, nhay den phan tu ke tiep (moi phan tu la 4 byte) b do # nhay den do ndo: la $a0, MangVuaNhap # in thng bao xuat addi $v0, $0, 4 syscall la $t0, mang # gan di chi mang cho t0 addi $s1, $s0, 0 # s1 = s0 = so luong phan tu do_1: # Xuat tung phan tu beq $s1, 0, ndo_1 # khi s1 < 0 thi nhay den ndo_1 lw $t2, ($t0) # ghi dia chi t0 vao t2, tro toi phan tu mang addi $a0, $t2, 0 # in t2, con tro phan tu, ra man hinh addi $v0, $0, 1 syscall la $a0, KhoangTrang # in khoang trang addi $v0, $0, 4 syscall addi $s1, $s1, -1 # giam di so luong can in di 1 addi $t0, $t0, 4 # nhay den phan tu ke tiep b do_1 # lap lai ndo_1: # Nhap vao 1 so nguyen n, tinh tong cac phan tu tu 1 toi n addi $v0, $0, 4 # in thong bao nhap so luong phan tu la $a0, NhapN syscall addi $v0 ,$0, 5 # nhap n syscall add $s0, $0, $v0 # so luong phep tinh dang nam trong $s0 add $t0, $0, $0 # bien chay la $t0 add $s1, $0, $0 # Tong la $s1 addi $s2, $0, 1 # s2 = 1, bat dau tu 1 Next: addi $t1, $t0, 1 ble $t0, $s0, VongLap # dieu kien dung: t0 <= s0 ( i < n), neu chua dat thi nhay den VongLap # Khi da tinh xong la $a0, KetQua # in thong bao ket qua addi $v0, $0, 4 syscall addi $a0, $s2, 0 # in so 1 addi $v0, $0, 1 syscall addi $v0,$0,4 # in chu " den " la $a0, den syscall addi $a0, $t0, 0 # in n addi $v0, $0, 1 syscall la $a0, LA addi $v0,$0,4 # in " la: " syscall # In ket qua addi $v0, $0, 1 add $a0, $0, $s1 syscall j EXIT VongLap: # qua trinh tinh toan add $s1, $s1, $t0 # s1 += i; addi $t0, $t0, 1 # buoc nhay, i + 1 j Next EXIT: # Nhap 1 chuoi, xuat ra chuoi in nguoc la $a0, NhapChuoi # in thong bao nhap addi $v0, $0, 4 syscall addi $a1, $0, 100 # khoi tao bo dem de nhap 100 ki tu addi $v0, $0, 8 # nhap chuoi la $a0, str # luu ket qua vua nhap vao bien str syscall addi $t1, $0, 0 # t1 = 0 la $a0, DaoNguoc # in thong bao ket qua addi $v0, $0, 4 syscall lap: lbu $t0, str($t1) beqz $t0, khoiTao # t0 = 0 thi nhay den khoiTao addi $t1, $t1, 1 j lap khoiTao: # khoi tao i, j de duyet tung phan tu cua 2 chuoi addi $t1, $t1, -1 # i = str.length() - 1, chay tu cuoi len dau addi $t2, $0, 0 # j = 0, chay tu dau chuyenDoi: # qua trinh bien doi chuoi blt $t1, $0, hoanThanh # t1 < 0 th? xong. lb $t3, str($t1) # t3 = str[i] sb $t3, revstr($t2) # t3 = revstr[j] subi $t1, $t1, 1 # i - 1 addi $t2, $t2, 1 # j + 1 j chuyenDoi hoanThanh: # sau khi hoan thanh la $a0, revstr addi $v0, $0, 4 # in ket qua syscall