Middle Node Of Linked List

# Definition for singly-linked list. # class ListNode(object): # def __init__(self, x): # self.val = x # self.next = None class Solution(object): def middleNode(self, head): """ input: ListNode head return: ListNode """ # write your solution here if (head == None): return None else: slow = head fast = head while(fast != None and fast.next != None and fast.next.next != None): fast = fast.next.next slow = slow.next return slow

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