#include <stdio.h>
#include <ctype.h>
#include <math.h>
int main ()
{
int L, O, G, I, C, n, l, o, g, i, c, m, k;
int D, E, d1, d2, e1, e2;
int w;
printf("Pazl 1\n");
printf("(L + O + G + I + C)^3 = LOGIC\n");
printf("\n");
for (n = 10000; n < 99999; n++) {
L = n / 10000;
O = (n / 1000) % 10;
G = ((n / 100) % 100) % 10;
I = (((n / 10) % 1000) % 100) % 10;
C = (((n % 10000) % 1000) % 100) % 10;
k = L + O + G + I + C;
m = pow (k, 3);
l = m / 10000;
o = (m / 1000) % 10;
g = ((m / 100) % 100) % 10;
i = (((m / 10) % 1000) % 100) % 10;
c = (((m % 10000) % 1000) % 100) % 10;
if((L == l) && (O == o) && (G == g) && (I == i) && (C == c))
printf("%d %d %d %d %d\n", L, O, G, I, C);
}
printf ("\nPazl 2\n");
printf("C^L = LOGIC\n");
printf("\n");
for (n = 10000; n < 99999; n++) {
L = n / 10000;
O = (n / 1000) % 10;
G = ((n / 100) % 100) % 10;
I = (((n / 10) % 1000) % 100) % 10;
C = (((n % 10000) % 1000) % 100) % 10;
m = pow (C, L);
l = m / 10000;
o = (m / 1000) % 10;
g = ((m / 100) % 100) % 10;
i = (((m / 10) % 1000) % 100) % 10;
c = (((m % 10000) % 1000) % 100) % 10;
if (((C == c) && (L == l)) && ((O == o) && (G == g) && (I == i)))
printf("%d %d\n", C, L);
}
printf("\nPazl 3\n");
printf("(DD)^E = DEED\n");
printf("\n");
w = 0;
for (n = 1000; n <= 9999; n++) {
D = n / 1000;
E = (n / 100) % 10;
k = pow (D, 2);
m = pow (k, E);
d1 = m / 1000;
e1 = (m / 100) % 10;
e2 = ((m / 10) % 100) % 10;
d2 = ((m % 1000) % 100) % 10;
if ((D == d1) && (E == e1) && (E == e2) && (D == d2)) {
printf(" D = %d E = %d\n", D, E);
} else {
if(w == 0) {
w += 1;
printf("Reshenia net\n");
}
}
}
getchar();
}
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