answer (Компл. числ. Формула сложного радикала)

#include "stdafx.h"//del #include <iostream> #include <cmath> #include <complex> using namespace std; void printC(complex<double > result) { if (result.imag() == 0) cout << "answer= " << result.real() << endl; else if (result.imag() == 1) cout << "answer= " << result.real() << " + i" << endl; else cout << "answer= " << result.real() << " + " << result.imag() << "i" << endl; } complex<double> funcLeft(int A, int B, int plus) { complex<double > result(0, 0); complex<double > a(A, 0); complex<double > b(B, 0); if (plus == 1) result = sqrt(a + sqrt(b)); else result = sqrt(a - sqrt(b)); return result; } complex<double> funcRight(int A, int B, int plus) { complex<double > result(0, 0); complex<double > a(A, 0); complex<double > b(B, 0); complex<double > two(2, 0); if (plus == 1) result = sqrt((a + sqrt(a*a - b) / two)) + sqrt((a - sqrt(a*a - b) / two)); else result = sqrt((a + sqrt(a*a - b) / two)) - sqrt((a - sqrt(a*a - b) / two)); return result; } int main() { complex<double> result(0, 0); int aStart; cout << "aStart= "; cin >> aStart; int aEnd; cout <<endl << "aEnd= "; cin >> aEnd; int bStart; cout << endl << "bStart= "; cin >> bStart; int bEnd; cout << endl << "bEnd= "; cin >> bEnd; cout << endl << "======================================= " << endl; for (int A = aStart; A <= aEnd; A++) { for (int B = bStart; B <= bEnd; B++) { cout << endl << "A = " <<A << endl; cout << endl << "B = " <<B <<endl; cout << endl << "!!!!!!!!!!!!Plus: !!!!!!!!!!!!!!" << endl; cout << endl << "Left: " << endl; result = funcLeft(A, B, 1); printC(result); cout << endl << "Right: " << endl; result = funcRight(A, B, 1); printC(result); cout << endl << "!!!!!!!!!!!!Minus: !!!!!!!!!!!!!!" << endl; cout << endl << "Left: " << endl; result = funcLeft(A, B, 0); printC(result); cout << endl << "Right: " << endl; result = funcRight(A, B, 0); printC(result); } cout << endl << "======================================= " << endl; } return 0; }