# Check to see if a string has the same amount of 'x's and 'o's.
# The method must return a boolean and be case insensitive. The string can contain any char.
def xo(s):
s = s.lower()
if s.count('x') != s.count('o'):
return False
elif s.count('x') < 0 or s.count('o') < 0:
return True
elif s.count('x') == s.count('o'):
return True
# XO("ooxx") => true
# XO("xooxx") => false
# XO("ooxXm") => true
# XO("zpzpzpp") => true // when no 'x' and 'o' is present should return true
# XO("zzoo") => false
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